A=49x^2+28x+4

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Solution for A=49x^2+28x+4 equation: 



=49A^2+28A+4

We move all terms to the left:

-(49A^2+28A+4)=0

We get rid of parentheses

-49A^2-28A-4=0

a = -49; b = -28; c = -4;
Δ = b2-4ac
Δ = -282-4·(-49)·(-4)
Δ = 0
Delta is equal to zero, so there is only one solution to the equation

                              Stosujemy wzór:
$A=\frac{-b}{2a}=\frac{28}{-98}=-2/7$

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